4^2+x=(x+1)-3

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Solution for 4^2+x=(x+1)-3 equation: 



4^2+x=(x+1)-3

We move all terms to the left:

4^2+x-((x+1)-3)=0

We add all the numbers together, and all the variables

x-((x+1)-3)+16=0



We calculate terms in parentheses: -((x+1)-3), so:

(x+1)-3

We get rid of parentheses

x+1-3

We add all the numbers together, and all the variables

x-2

Back to the equation:

-(x-2)



We get rid of parentheses

x-x+2+16=0

We add all the numbers together, and all the variables

18!=0

There is no solution for this equation

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